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UoL CS Notes

Description Logic

COMP304 Lectures

Description logic is used to describe ontologies:

An ontology defines objects by their relations to other objects.

We have seen ontologies before in COMP111:

Language of ALC

Attribute logic with complement (ALC) is a multi-agent modal logic (with different symbols).

An ALC signature is a triple $\Sigma=(\mathcal O, \mathcal C, \mathcal R)$ where:

  • $\mathcal O$ is a set of object names.
  • $\mathcal C$ is a set of atomic concepts.
  • $\mathcal R$ is a set of relations symbols.

This is comparable to the set of propositional atoms and the set of agents that were used in propositional and modal logic.

Formulas of ALC are called concepts. Concepts are denoted by $X,Y,Z,X_1,\ldots$ and given by:

\[X::=\top\mid\bot\mid A\mid\neg X\mid X\sqcup X|X\sqcap X| \forall r.X\mid\exists r.X\]

where $A\in\mathcal C$ and $r\in\mathcal R$.

  • An object name $o\in O$ describes a single object. There can be objects without names, but every name refers to exactly one object. No object has multiple names.
    • Ann, Bob; Fido.
  • An atomic concept is a single word that describes a number of objects.
    • Parent, father, male, person; dog.
  • A concept combines one or more atomic concepts into a more complex description:
    • A parent who is male.
    • A person who has a t least one child that is a parent.

The final two concepts are defined as:

  • $\exists r,X$ indicates those objects that stand in the relation $r$ to some object that is $X$:
    • $\exists\text{hasChild}.\text{female}$ is someone who has at least one daughter.
  • $\forall r.X$ indicates those objects taht only stand in the relation $r$ to objects that are $X$:
    • $\forall\text{hasChild}.\neg\text{female}$ is someone who only has children that are not $\text{female}$ (a person whose children, if any, are all sons).

Additionally:

  • $\top$ defines any object.
  • $\bot$ indicates no objects.

ALC Language Examples

  • A person who has at least one child:
    • $\text{person}\sqcap\exists\text{hasChild}.\top$
  • A parent who is male:
    • $\text{parent}\sqcap\text{male}$
  • A person who has at least one child that is a parent:
    • $\text{person}\sqcap\exists\text{hasChild}.\text{parent}$

Semantics of ALC

ALC Interpretations

In description logic we refer to models as interpretations.

Let $\Sigma=(\mathcal O,\mathcal C,\mathcal R)$ be a signatire. An interpretation $\mathcal I$ over $\Sigma$ is a pair $(\Delta,\cdot^\mathcal I)$ where:

  • $\Delta$ is a domain (a non-empty set).
  • $\cdot^\mathcal I$ maps $\mathcal O$ to $\Delta$:
    • For every $o\in \mathcal O$, $o^\mathcal I\in\Delta$.
  • $\cdot^\mathcal I$ maps $\mathcal C$ to $2^\Delta$:
    • For every $C\in \mathcal C$, $C^\mathcal I\subseteq\Delta$.
  • $\cdot^\mathcal I$ maps $\mathcal R$ to $2^{\Delta\times\Delta}$:
    • For every $r\in \mathcal R$, $r^\mathcal I\subseteq\Delta\times\Delta$.

and further more $o^\mathcal I_1\neq o^\mathcal I_2$ unless $o_1=o_2$

What are Interpretations

  • $\mathcal O$ are a set of names of individuals, $\mathcal C$ a set of names of concepts and $\mathcal R$ a set of names of relations.
  • $\Delta$ are things that actually exist.
  • The map $\cdot^\mathcal I$ tells us who has which name:
    • $\text{Ann}^\mathcal I$ is the person who has the name Ann.

Drawing Interpretations

Suppose:

  • $\mathcal O={\text{Ann, Bob, Claire}}$, $\mathcal C={\text{person, dog, parent, grandparent}}$, $\mathcal R={\text{hasChild}}$
  • $\Delta={u,x,y,z}$
  • $\text{Ann}^\mathcal I=x$, $\text{Bob}^\mathcal I=y$, $\text{Claire}^\mathcal I=z$
  • $\text{person}^\mathcal I={x,y,z}$, $\text{dog}^\mathcal I={u}$, $\text{parent}^\mathcal I={x,y}$, $\text{grandparent}^\mathcal I=\emptyset$
  • $\text{hasChild}^\mathcal I={(x,z),(y,z)}$

This can be drawn as:

graph LR
y[y<br>Bob,person,parent] -->|hasChild| z[z<br>Claire,person]
x[x<br>Ann,person,parent] -->|haschild| z
u[u<br>dog]

Lifting Interpretations

Assume the following:

  • $A^\mathcal I$ - Interpretation of the atomic concepts $A$

    Those objects that satisfy $A$.

Interpretation $\mathcal I$ can be lifted - we can determine whether $X^\mathcal I$ in the following way:

  • $\top^\mathcal I=\Delta$
  • $\bot^\mathcal I=\emptyset$
  • $(X\sqcup Y)^\mathcal I=X^\mathcal I\cup Y^\mathcal I$

    The objects that satisfy $X\sqcup Y$ are those objects that satisfy either $X$ or $Y$.

  • $(X\sqcap Y)^\mathcal I=X^\mathcal I\cap Y^\mathcal I$

    The objects that satisfy $X\sqcap Y$ are those objects that satisfy both $X$ and $Y$.

Additionally we have:

  • $(\forall r,X)^\mathcal I={u\in\Delta\mid\forall y\in\Delta:(u,y)\in r^\mathcal I\implies y\in X^\mathcal I}$

    The objects that satisfy $\forall r.X$ are those objects that are related by $r$ only to objects that satisfy $X$.

  • $(\exists r,X)^\mathcal I={u\in\Delta\mid\exists y\in\Delta:(u,y)\in r^\mathcal I\text{ and } y\in X^\mathcal I}$

    The objects that satisfy $\exists r.X$ are those objects that are related by $r$ to at least one objects that satisfies $X$.

Lifting Interpretations Example

Considering our previous example:

graph LR
y[y<br>Bob,person,parent] -->|hasChild| z[z<br>Claire,person]
x[x<br>Ann,person,parent] -->|haschild| z
u[u<br>dog]

we can solve the following:

  • $(\text{parent}\sqcup\text{dog})^\mathcal I={x,y,u}$
  • $(\forall\text{hasChild}.\bot)^\mathcal I={z,u}$
  • $(\text{person}\sqcap\text{dog})^\mathcal I=\emptyset$